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0.45x^2+70x-9075=0
a = 0.45; b = 70; c = -9075;
Δ = b2-4ac
Δ = 702-4·0.45·(-9075)
Δ = 21235
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-\sqrt{21235}}{2*0.45}=\frac{-70-\sqrt{21235}}{0.9} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+\sqrt{21235}}{2*0.45}=\frac{-70+\sqrt{21235}}{0.9} $
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